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Evaluate: `int(4x+1)/(x^2+3x+2) dx` |
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Answer» `I=int(4x+1)/(x^(2)+3x+2)dx` `=int(2(2x+3)-5)/(x^(2)+3x+2)dx` `=2int(2x+3)/(x^(2)+3x+2)dx-5int(1)/(x^(2)+3x+2)dx` `=2log|x^(2)+3x+2|-5int(1)/(x^(2)+3x+(9//4)-(9//4)+2)dx` `=2log|x^(2)+3x+2|-5int(1)/((x+3//2)^(2)-(1//2)^(2))dx` `=2log|x^(2)+3x+2|-5(1)/(2(1//2))log|(x+(3)/(2)-(1)/(2))/(x+(3)/(2)+(1)/(2))|+C` `=2log|x^(2)+3x+2|-5log|(x+1)/(x+2)|+C` |
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