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Evaluate:\(\int\cfrac{e^x}{(e^{2x}+1)}dx\) ∫ ex/(e2x+1) |
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Answer» To find: \(\int\cfrac{e^x}{(e^{2x}+1)}dx\) Formula Used: \(\int\cfrac{dx}{1+x^2}=tan^{-1}x\) Let y = ex … (1) Differentiating both sides, we get ' dy = ex dx Substituting in given equation, \(\Rightarrow\) \(\int\cfrac{dy}{y^2+1}\) ⇒ tan-1 y From (1), ⇒ tan-1 (ex ) Therefore, \(\int\cfrac{e^x}{(e^{2x}+1)}dx=tan^{-1}(e^x)+c\) |
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