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Evaluate:`int(e^(2x)-2e^x)/(e^(2x)+1)dx` |
Answer» Correct Answer - `(1)/(2)log(e^(2x)+1)-2 tan^(-1)(e^(x))+C` `int(e^(2x)-2e^(x))/(e^(2x)+1)dx=(1)/(2)int(2e^(2x))/(e^(2x)+1)dx-2int(e^(x)dx)/((e^(x))^(2)+1) ` `=(1)/(2)log(e^(2x)+1)-2int(dz)/(z^(2)+1), " where " z=e^(x) ` ` =(1)/(2)log(e^(2x)+1)-2 tan^(-1)(e^(x))+C` |
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