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Evaluate:`int(e^(logx)+sinx)cosxdx` |
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Answer» Correct Answer - `"x sin x" + "cos x" -("cos"2x)/(4)+c` Let `I=int (e^(log x)+sin x)cos x dx` `=int (x+sin x) cos x dx` `=int x cos x dx +(1)/(2)int(sin 2x)dx` `=(x*sin x -int 1*sin x dx)-(cos 2 x)/(4)+c` `=x sin x + cos x -(cos 2 x)/(4)+c` |
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