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Evaluate: \(\int\limits_1^2 log\,x\,dx\)∫ log x dx, x ∈[1,2] |
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Answer» \(=\int\limits_1^2 log(x)dx=xlog(x)-(x)\) \(=2log(2)-(2)-1log(1)+(1)\) = 2log(2)-1 |
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