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Evaluate:  \(\int\limits_1^2 log\,x\,dx\)∫ log x dx, x ∈[1,2]

Answer»

\(=\int\limits_1^2 log(x)dx=xlog(x)-(x)\) 

\(=2log(2)-(2)-1log(1)+(1)\)

= 2log(2)-1



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