1.

Evaluate:  \(\int\limits_{-4}^{-1}\cfrac{dx}{x}\)∫ dx/x, x ∈[-1,-4]

Answer»

\(\int\limits_{-4}^{-1}\cfrac{dx}{x}=-[logx]\)

=[log(-1)-log(-4)] 

=-[log(-4)-log(-1)]

=\(-\left[log\left(\cfrac{-4}{-1}\right)\right]\)

=-log 4



Discussion

No Comment Found