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Evaluate: \(\int\limits_{-4}^{-1}\cfrac{dx}{x}\)∫ dx/x, x ∈[-1,-4] |
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Answer» \(\int\limits_{-4}^{-1}\cfrac{dx}{x}=-[logx]\) =[log(-1)-log(-4)] =-[log(-4)-log(-1)] =\(-\left[log\left(\cfrac{-4}{-1}\right)\right]\) =-log 4 |
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