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Evaluate\(\int\limits_{-\pi/2}^{\pi/2}\) x cos2x dx |
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Answer» Let I = \(\int\limits_{-\pi/2}^{\pi/2} \) x cos2x dx f(x)=xcos2x f(-x)=(-x)cos2(-x) =-xcos2x =-f(x) Hence, f(x) is an odd function. Since, \(\int\limits_{-a}^af(x)dx=0\) if f(x) is an odd function. Therefore, I = 0. |
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