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Evaluate `int(log_(e)x)^(2)dx` |
Answer» Correct Answer - `x*(log_(e)x)^(2)-2(xlog_(e)x-x)+c ` `int 1*(log_(e)x)^(2)dx` `=x*(log_(e)x)^(2)-int 2(log_(e)x)/(x)*xdx ` `=x*(log_(e)x)^(2)-2int log_(e)xdx ` `=x*(log_(e)x)^(2)-2(xlog_(e)x-x)+c ` |
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