1.

Evaluate:`int("log"(tanx/2)/(sinx)dx`

Answer» `(d)/(dx)[log("tan"(x)/(2))]=((1)/(2)"sec"^(2)(x)/(2))/("tan"(x)/(2))=(1)/(sinx)`
Now `int(log("tan"(x)/(2)))/(sinx)dx=intlog("tan"(x)/(2))(d)/(dx)[log("tan"(x)/(2))]dx`
`=([log("tan"(x)/(2))]^(2))/(2) +C`


Discussion

No Comment Found

Related InterviewSolutions