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Evaluate:`int("log"(tanx/2)/(sinx)dx` |
Answer» `(d)/(dx)[log("tan"(x)/(2))]=((1)/(2)"sec"^(2)(x)/(2))/("tan"(x)/(2))=(1)/(sinx)` Now `int(log("tan"(x)/(2)))/(sinx)dx=intlog("tan"(x)/(2))(d)/(dx)[log("tan"(x)/(2))]dx` `=([log("tan"(x)/(2))]^(2))/(2) +C` |
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