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Evaluate `int sec^(-1)xdx` |
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Answer» Put `sec^(-1)x=t` so that x =`sect` and `dx=sect tant dt` `therefore intsec^(-1)xdx=intt(sect tant) dt = t(sect)-int(1.sectdt)` `tsect=ln|sect+tant|+C` `tsect-ln|sect + sqrt(sec^(2)t-1)|+C=x(sec^(-1)x)-ln|x+sqrt(x^(2)-1)|+C` |
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