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Evaluate `int(sin^(6)x)/(cos^(8)x)dx` |
Answer» Correct Answer - `(tan^(7)x)/(7)+C` `int(sin^(6)x)/(cos^(8)x)dx=int(sin^(6)x)/(cos^(6)x)xx(1)/(cos^(2)x)dx` `=inttan^(6)x sec^(2)xdx` `=(tan^(7)x)/(7)+C` |
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