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Evaluate `int sin x cos x cos2x cos 4x cos 8x dx` |
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Answer» Correct Answer - `-(1)/(256)cos16x+C` `I= intsin x cos x cos2x cos 4x cos 8x dx` `=(1)/(2)int sin2x cos2x cos4x cos8x dx` `=(1)/(4)intsin4xcos4xcos8xdx` ` = (1)/(8)intsin8xcos8xdx` ` =(1)/(16)intsin16x dx = (-1)/(256)cos16x+C` |
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