1.

Evaluate `int(sqrt(tanx))/(sinx cosx)dx`

Answer» Correct Answer - `2 sqrt(tanx)+C`
`int(sqrt(tanx))/(sinx cosx)dx=int(sqrt(tanx)(1)/("cos"^(2)x))/((sinx cosx)/("cos"^(2)x))dx`
`=int(sqrt(tanx)sec^(2)x)/(tanx)dx=int(tan x)^(-1//2)sec^(2)x dx`
`=((tan x)^(1//2))/(1//2)+C=2 sqrt(tanx)+C`


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