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Evaluate `int tan^(2)x sin^(2)xdx` |
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Answer» Correct Answer - `tanx-(3)/(2)x+(sin2x)/(4)+C` `int tan^(2)x sin^(2)xdx=int(sin^(4)x)/(cos^(2)x)dx` `=int(sin^(2)x(1-cos^(2)x))/(cos^(2)x)dx` `=int(tan^(2)x-sin^(2)x)dx` `=int(sec^(2)x-1-(1-cos2x)/(2))dx` `=tanx-(3)/(2)x+(sin2x)/(4)+C` |
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