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Evaluate `int(tanx)/(secx+tanx)dx` |
Answer» Correct Answer - `secx-tanx+x+C` `int(tan)/(secx+tanx)dx=int(tanx(secx-tanx))/((secx+tanx)(secx-tanx))dx` `=int(tanx(secx-tanx))/(sec^(2)x-tan^(2)x)dx` `=int(secxtanx-tan^(2)x)dx` `=int(secxtanxdx-int(sec^(2)x-1)dx` `=int(secxtanxdx-intsec^(2)xdx+int1dx` `=secx-tanx+x+C` |
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