1.

Evaluate `int(tanx)/(secx+tanx)dx`

Answer» Correct Answer - `secx-tanx+x+C`
`int(tan)/(secx+tanx)dx=int(tanx(secx-tanx))/((secx+tanx)(secx-tanx))dx`
`=int(tanx(secx-tanx))/(sec^(2)x-tan^(2)x)dx`
`=int(secxtanx-tan^(2)x)dx`
`=int(secxtanxdx-int(sec^(2)x-1)dx`
`=int(secxtanxdx-intsec^(2)xdx+int1dx`
`=secx-tanx+x+C`


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