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Evaluate: `int((x-1)^2)/(x^4+x^2+1) dx` |
Answer» Correct Answer - `(1)/(sqrt3)tan^(-1)(x-1//x)/(sqrt3)-(2)/(sqrt3)tan^(-1)((2x^(2)+1)/(sqrt3))+C` `int((x-1)^(2))/(x^(4)+x^(2)+1)dx` `=int(x^(2)+1)/(x^(4)+x^(2)+1)dx-int(2x)/(x^(4)+x^(2)+1)dx` `=int(1+(1)/(x^(2)))/((x-(1)/(x))^(2)+3)dx-int(2x)/((x^(2)+(1)/(2))^(2)+(3)/(4))dx` `=(1)/(sqrt3)tan^(-1).(x-1//x)/(sqrt3)-(2)/(sqrt3)tan^(-1)((2x^(2)+1)/(sqrt3))+C` |
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