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Evaluate : `int(x^(2)-4)/(x^(4)+9x^(2)+16)dx` |
Answer» Correct Answer - 5 `I=int(x^(2)-4)/(x^(4)+9x^(2)+16)dx` Divide both numberator and denominator by `x^(2)` `I=int((1-(4)/(x^(2))))/(x^(2)+9+(16)/(x^(2)))dx=int((1-(4)/(x^(2))))/((x+(4)/(x))^(2)+1)dx` `"Put "u=x+(4)/(x),du=(1-(4)/(x^(2)))dx` `I=int(du)/(u^(2)+1)=tan^(-1)(u)+B` `=tan^(-1)(x+(4)/(x))+C` |
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