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Evaluate:`int((x-x^3)^(1/3))/(x^4)dx` |
Answer» Correct Answer - ` -(3)/(8)((1)/(x^(2))-1)^(4//3)+C` `I=int((x-x^(3))^(1//3))/(x^(4))dx=int(((1)/(x^(2))-1)^(1//3))/(x^(3))dx` ` "Putting " (1)/(x^(2))=t, (1)/(x^(3))dx= -(dt)/(2), " we get" ` `I= -(1)/(2)int t^(1//3)dt= -(3)/(8)t^(4//3)+C= -(3)/(8)((1)/(x^(2))-1)^(4//3)+C` |
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