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Evaluate: `int1/(e^x+e^(-x)) dx` |
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Answer» Correct Answer - `tan^(-1)(e^(x))+C` `I=int(dx)/(e^(x)+e^(-x))=int(e^(x)dx)/(e^(2x)+1)` Let `e^(x)=t.` ` :. e^(x)dx=dt` ` :. I=int(dt)/(t^(2)+1)=tan^(-1)t+C=tan^(-1)(e^(x))+C` |
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