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Evaluate:`int1/([(x-1)^3(x+2)^5]^(1/4))dx` |
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Answer» `I=int(1)/(((x-1)/(x+2))^(3//4)(x+2)^(2))dx` Let `(x-1)/(x+2)=t " or " (3dx)/((x+2)^(2))=dt` ` :. I=(1)/(3)int(1)/(t^(3//4))dt=(1)/(3)((t^(1//4))/(1//4))+C` `=(4)/(3)t^(1//4)+C=(4)/(3)((x-1)/(x+2))^(1//4)+C` |
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