1.

Evaluate : inte^(2x)*(-sinx+2cosx)dx.

Answer»

Solution :We have
`I=inte^(2X)*{cosx-sinx}DX=2inte^(2x)cosxdx-inte^(2x)sinxdx`
`=2*{:[cosx*(e^(2x))/(2)-int(-sinx)*(e^(2x))/(2)dx]:}-inte^(2x)sinxdx`[integrating `e^(2x)` cos x by PARTS]
`=e^(2x)cosx+inte^(2x)sinxdx-inte^(2x)sinxdx+C`
`=e^(2x)cosx+C`.


Discussion

No Comment Found

Related InterviewSolutions