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Evaluate:`inttan^(-1)sqrt((1-x)/(1+x))dx` |
Answer» Correct Answer - `theta cos 2 theta-(sin2 theta)/(2)+C` ` I=int tan^(-1)sqrt((1-x)/(1+x))dx` ` "Let "x=cos2 theta " or "dx=-2sin2 theta d theta ` `:. I=int tan^(-1)sqrt((1-cos2 theta)/(1+cos2 theta))(-2sin2 theta)d theta ` `=-2int tan^(-1)(tan theta)sin2 theta d theta ` `=-2int theta sin 2 theta d theta ` `=-2[-(theta cos2 theta)/(2)+int(cos2 theta)/(2) d theta]` `=theta cos 2 theta-(sin2 theta)/(2)+C` |
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