1.

Evaluate : ∫logx dx.

Answer»

= ∫logx dx = ∫logx.1 dx 

= ∫uv dx = u∫v dx – ∫[d/dx x∫vdx] dx 

Iogx ∫1. dx ∫[d/dx(logx)x∫1.dx] dx 

= 1ogx(x)∫(1/x xx) dx 

= xlogx - ∫1. dx 

I = x logx – x + c



Discussion

No Comment Found

Related InterviewSolutions