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Evaluate lower quartile and upper quartile from the following series.Variable510152025303540Frequency161822212414119 |
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Answer»
Q1 = size of \((\frac{N+1}4)^{th}\) item Or, Q1 = size of \((\frac{135+1}{4})^{th}\) item = Q1 = 34th item Upper Quartile Q1 = size of 3 \((\frac{N+1}{4})^{th}\) item or, Q1 = size of 3 \((\frac{135+1}{4})^{th}\) item = Q1 = 102nd item This corresponds to 115 in the cumulative frequency. Hence, upper quartile is 30. |
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