1.

Evaluate: \(\rm \int \frac{x+4}{(x+5)^2}dx\)1. \(\rm log\left | x+5 \right |-\frac{1}{(x+5)}+C\)2. \(\rm 2log\left | x+5 \right |+C\)3. \(\rm log\left | x+5 \right |+\frac{1}{(x+5)}+C\)4. \(\rm log\left | x+5 \right |+\frac{1}{(x+5)^2} + c\)

Answer» Correct Answer - Option 3 : \(\rm log\left | x+5 \right |+\frac{1}{(x+5)}+C\)

Concept:

  • \(\rm \int\frac{1}{x+a}dx=log|x+a|+C\)
  • \(\rm \int\frac{1}{(x+a)^n}dx=\frac{1}{(1-n)(x+a)^{n+1}}+C\)

Calculation:

\(\rm \int \frac{x+4}{(x+5)^2}dx\)

This integrand is a proper rational fraction. So, by using the form of a partial fraction, we can write it as:

\(\rm \frac{x+4}{(x+5)^2}=\frac{A}{x+5}+\frac{B}{(x+5)^2}\)

This gives,  x + 4 = Ax + 5A + B 

By comparing the coefficient of x and constant terms on both sides, we get A = 1 and 5A + B = 4

By solving these equation, we get  A = 1 and B = -1

 \(⇒ \rm \frac{x+4}{(x+5)^2}=\frac{1}{x+5}-\frac{1}{(x+5)^2}\)  

\(\rm \int \frac{x+4}{(x+5)^2}dx=\int\frac{1}{x+5}dx-\int\frac{1}{(x+5)^2}dx\)

⇒ \(\rm \int\frac{x+4}{(x+5)^2}dx=log\left | x+5 \right |+\frac{1}{(x+5)}+C\)   

Hence, option 3 is correct.


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