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Evaluate root20 + root 20 + root20................

Answer»

Let there be X number
then x= √20+( √20+( √ 20...
x= sqrt(20+x)
squaring both sides
x2 =20 +x
x2 -x-20=0
x2-5x+4x-20=0
x (x-5)+4 (x-5 )=0
(x+4)(x-5)=0
x= -4 or 5
since x cannot be -ve x=5



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