1.

Evaluate `sqrt(26)` correct upto four places of decimal.

Answer» `sqrt(26)=(25+1)^((1)/(2))=5[1+(1)/(25)]^((1)/(2))`
`=5[1+(1)/(2)(1)/(25)]`
`=5[1+0.02]`
`=p1.02]=5.10`
`=5.10` (correct to two places of decimal


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