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Evaluate `sqrt(26)` correct upto four places of decimal. |
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Answer» `sqrt(26)=(25+1)^((1)/(2))=5[1+(1)/(25)]^((1)/(2))` `=5[1+(1)/(2)(1)/(25)]` `=5[1+0.02]` `=p1.02]=5.10` `=5.10` (correct to two places of decimal |
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