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Evaluate Tan75° using 30° and 45°. |
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Answer» Tan θ = Opposite side/Adjacent side tan 0° = 0/1 = 0 tan 30° = [(√1/4)/√(3/4)] = 1/√3 tan 45° = 1 tan 60° = [(√3/2)/(½)] = √3 tan 90° = 1/0 = ∞ tan 75° can be written as tan(75°) = tan(45° + 30°) tan (A + B) = [tan A + tan B]/[1 – tan A tan B] tan(75°) = [tan(45°) + tan(30°)]/[1 – tan(45°)tan(30°)] tan(75°) = [1 + 1/√(3)]/(1 – 1/√(3)] tan(75°) = (√(3) + 1)/(√(3) – 1) |
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