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Evaluate Tan75° using 30° and 45°.

Answer»

Tan θ = Opposite side/Adjacent side

tan 0° = 0/1 = 0

tan 30° = [(√1/4)/√(3/4)] = 1/√3

tan 45° = 1

tan 60° = [(√3/2)/(½)] = √3

tan 90° = 1/0 = ∞

tan 75° can be written as

tan(75°) = tan(45° + 30°)

tan (A + B) = [tan A + tan B]/[1 – tan A tan B]

tan(75°) = [tan(45°) + tan(30°)]/[1 – tan(45°)tan(30°)]

tan(75°) = [1 + 1/√(3)]/(1 – 1/√(3)]

tan(75°) = (√(3) + 1)/(√(3) – 1)



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