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Evaluate the following determinants.[[1,x,y],[0,sinx,siny],[0,cosx,cosy]] |
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Answer» Solution :`[[0,x,y],[0,sinx,SINY],[0,COSX,COSY]]=1[[sinx,siny],[cosx,cosy]]` =sinxcosy-cosxsiny=sin(x-y). |
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