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Evaluate the following integrals: int_0^(pi/2) cos^2x dx |
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Answer» Solution :`int_0^(pi/2) cos^2x DX` =`int_0^(pi/2) (1+cos 2x)/2 dx = 1/2[x+(SIN2X)/2]_0^(pi/2)` =`1/2 ((pi/2+0)-(0+0)) = pi/4` |
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