1.

Evaluate the following integrals: int_0^(pi/4) sin2xdx

Answer»

Solution :`int_0^(pi/4) SIN 2x DX = ((-COS 2x)/2)_0^(pi/4)`
= `-1/2(cos2x)_0^(pi/4)`
=`-1/2 (cos pi/2 - cos 0)`
=-1/2(0-1) = 1/2


Discussion

No Comment Found

Related InterviewSolutions