Saved Bookmarks
| 1. |
Evaluate the following integrals: int_0^(pi/4) sin2xdx |
|
Answer» Solution :`int_0^(pi/4) SIN 2x DX = ((-COS 2x)/2)_0^(pi/4)` = `-1/2(cos2x)_0^(pi/4)` =`-1/2 (cos pi/2 - cos 0)` =-1/2(0-1) = 1/2 |
|