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Evaluate the following integrals: int_-1^1 (x+1) dx |
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Answer» SOLUTION :`int_-1^1 (x+1) DX = [x^2/2+x]_-1^1` =`(1^2/2+1)-((-1)^2/2 +(-1))` `1/2 +1-(1/2-1) = 3/2 +1/2 = 2` |
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