1.

Evaluate the following integrals: int_-1^1 (x+1) dx

Answer»

SOLUTION :`int_-1^1 (x+1) DX = [x^2/2+x]_-1^1`
=`(1^2/2+1)-((-1)^2/2 +(-1))`
`1/2 +1-(1/2-1) = 3/2 +1/2 = 2`


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