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Evaluate the following integrals int_1^4(dx/sqrtx)dx |
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Answer» SOLUTION :`int_1^4dx/(sqrtx)=int_1^4x^(-1/2)DX=[X^(1/2)/(1/2)]_1^4` `2{4^(1/2)-1^(1/2)}=2(2-1)=2` |
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