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Evaluate the following integrals int sqrtx (3x^2+2x+3) dx

Answer»

Solution :`int sqrtx (3X^2+2x+3)dx = int(3x^(1/2) X^2 + 2 x^(1/2)x +3 x^(1/2)) dx`
=`int(3x^(5/2) +2x^(3/2) +3x^(1/2)) dx = (3x^(5/2+1))/(5/2+1) + (2x^(3/2+1))/(3/2+1) + (3x^(1/2+1))/(1/2+1) +c = 6/7 x^(7/2) +4/5 x^(5/2) +2x^(5/2) +c`


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