1.

Evaluate the following integrals int(tan^2theta+1)/(tan^2theta-1)d theta

Answer»

Solution :`int(tan^2theta+1)/(tan^2theta-1)d THETA`
PUT `TANTHETA=t`
`sec^2theta d theta=DT`
`int(sec^2thetad theta )/(tan^2theta-1)`
`int(dt)/(t^2-1)=(1/2)Inabs(t-1)/(t+1)+C`
`(1/2)Inabs((tantheta-)/(tantheta+1)) +C`


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