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Evaluate the following:lim_(xtoinfty)log_e(1+a/x)^x |
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Answer» SOLUTION :`lim_(xtoinfty)log_e``(1+a/X)^x` `=log_e{lim_(xtoinfty)(1+a/x)^x}` `log_ee^a=alog_e` `e=a[thereforelim_(x to INFTY)(1+a/x)^x=e^a |
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