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Evaluate the following:sec-1(sec \(\frac{9\pi}5\)) |
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Answer» sec\((\frac{9\pi}5)\) can be written as sec\((2\pi-\frac{\pi}5)\) Also, we know sec(2π - θ) = sec(θ) ∴ sec \((2\pi-\frac{\pi}5)\) = sec \((\frac \pi 5)\) ∴ Now the given equation can be written as sec–1sec\((\frac \pi 5)\) As sec-1(sec x) = x Provided x ∈ [0,π] - \(\{\frac \pi 2\}\) ∴ we can write sec-1sec\((\frac{\pi}5)\) as \(\frac{\pi}5.\) |
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