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Evaluate the integral: ∫sin3 x cos x dx |
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Answer» It is given that ∫sin3 x cos x dx By taking sin x = t We get cos x = dt/dx It can be written as cos x dx = dt So we get = ∫t3 dt By integrating w.r.t t = t4/4 + c By substituting the value of t = sin4 x/4 + c |
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