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Evaluate: ∫x/(x2 + 1)(x + 1) dx |
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Answer» Let I = ∫x/(x2 + 1)(x + 1) dx Now, x/(x2 + 1)(x + 1) = (1/2)[(x + 1)/(x2 + 1) - (1/x + 1)] (partial function) So, I = (1/2)∫x/(x2 + 1) dx + ∫dx/(x2 + 1) - ∫dx/(x + 1) = (1/4) log(x2 + 1) + 1/2) tan-1 x - (1/2) log|x + 1| + k |
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