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Evaluate yourself1.Calculate the de. Bragile wavelength of anelectron that Pas been acceleratedfromrest througha potentialdifference Of I kev |
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Answer» Answer: We KNOW that, 1
mv 2 =K.E.=ev Charge on electron: 1.6×10 −19 coulombs Mass of electron=9.1×10 −31 kg 2 1
×9.1×10 −31 ×v 2 =1.6×10 −19 ×100 v 2 =2×1.6×10 −9 × 9.1×10 −31
100
v 2 = 0.0150
v=1.88×10 6 m/s Now, λ= mv h
∴λ=0.1226nm. |
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