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Evaluateint1/(sin^2xcos^2x)dx.

Answer»

SOLUTION :`INTDX/(sin^2xcos^2x)=INT(sin^2x+cos^2x)/(sin^2xcos^2x)dx=int((sin^2x)/(sin^2xcos^2x)+(cos^2x)/(sin^2xcos^2x))dxint(sec^2x+cosec^2x)dx=tanx-cotx+C`


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