1.

examination was held in two parts. Of the 630 examinees, appeared in onlypart and appeared in only the second part. The rest appeared in both the parts. FindThe number of examinees who appeared in both the parts.

Answer»

Examiners appeared in first part only=3/10*630=189Examiners appeared only in second part =2/15*630=84Thus examiners appeared in both=630-(189+84)=630-273=357...

1st exam=3/10×630=1892nd exam=2/15×630=84so,examiners who appeared in both=630-(189+84)630-273=357

1st exam=3/10*630=1892nd exam=2/15*630=84Both=630-(189+84)=630-273=357



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