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Examine Tables 6.1-6.3 and express The kinetic energy of an air molecule (10^(-21)J) in eV. |
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Answer» SOLUTION :The KINETIC energy of an air molecule is `(10^(-21)J)/(1.6xx10^(-19)J"/"eV) cong 0.0062 eV` This is the same as 6.2 MEV. |
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