1.

Examine Tables 61. -6.3 and express (a) the energy required to break one bond in DNA in eV, (b) The kinetic energyof an air molecule(10^(-21)J) in eV , (c ) The daily intake of a human adult in kilocalories .

Answer»

Solution :Energy required to break ONE bond of DNA is
`(10^(-20)J)/(1.6xx10^(-19)J"/"eV) CONG 0.06 eV`
Note `0.1 eV= 100 meV` (100 millielectron VOLT).


Discussion

No Comment Found