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Examine Tables 61. -6.3 and express (a) the energy required to break one bond in DNA in eV, (b) The kinetic energyof an air molecule(10^(-21)J) in eV , (c ) The daily intake of a human adult in kilocalories . |
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Answer» Solution :Energy required to break ONE bond of DNA is `(10^(-20)J)/(1.6xx10^(-19)J"/"eV) CONG 0.06 eV` Note `0.1 eV= 100 meV` (100 millielectron VOLT). |
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