Example 10: In the following figure, ABrectangle in which the segments

1.	Example 10: In the following figure, ABrectangle in which the segmentsas shown. Find the length of (AP + AQ).AP and AQ are drawn30°P 830°60 cm
Answer» In right angle triangle ABP, Sin theta = opposite/Hypotenuse Hence, sin 30 degree = 50/AP 1/2=50/AP AP=50*2 AP= 100 cm Also, Similaraly In right angle triangle ADQ sin 30 degree = 20/AQ AQ = 40 cm

Example 10: In the following figure, ABrectangle in which the segmentsas shown. Find the length of (AP + AQ).AP and AQ are drawn30°P 830°60 cm

Answer»

In right angle triangle ABP,

Sin theta = opposite/Hypotenuse

Hence,

sin 30 degree = 50/AP

1/2=50/AP

AP=50*2

AP= 100 cm

Also, Similaraly In right angle triangle ADQ

sin 30 degree = 20/AQ

AQ = 40 cm