Example 5 : Consider the numbers ", whhere n is a natarai nnber. heok

1.	Example 5 : Consider the numbers ", whhere n is a natarai nnber. heok wherhegthere is any value of n for which ends with the dips zen,
Answer» Let n be any natural number 1,2,3..........(4)1=4(4)2=16(4)3=64(4)4=256.... therefore 4^n never ends with 0 . And as it end with 6 and 4 thats why it is divisible by 2 Like my answer if you find it useful!

Example 5 : Consider the numbers ", whhere n is a natarai nnber. heok wherhegthere is any value of n for which ends with the dips zen,

Answer»

Let n be any natural number 1,2,3..........(4)1=4(4)2=16(4)3=64(4)4=256.... therefore 4^n never ends with 0 .

And as it end with 6 and 4 thats why it is divisible by 2

Like my answer if you find it useful!