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Example 8.7 The brakes applied to a carproduce an acceleration of 6 m s2 inthe opposite direction to the motion. Ifthe car takes 2 s to stop after theapplication of brakes, calculate thedistance it travels during this time. |
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Answer» hope this helps :) v=u-atv=0 a=6 t=2secu=at=6*2=12m/ss=ut-1/2at^2s=12*2-1/2*6*4s=24-12=12m v=u-atv=0 a=6 t=2secu=at=6*2=12m/ss=ut-1/2at^2s=12*2-1/2*6*4s=24-12=12m |
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