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Example 9.3 A motorcar is moving with avelocity of 108 km/h and it takes 4 s tostop after the brakes are applied.Calculate the force exerted by thebrakes on the motorcar if its mass alongwith the passengers is 1000 kg

Answer»

U = 108 km/h => 108×5/18 => 6×5 => 30 m/sv = 0m/st = 4sectherefore , a = (v-u)/t =>a = (0-30)/4 => a = -30/4 => -7.5 m/s²

force = mass × accelerationforce = 1000 kg × (-7.5) m/s²force = -7500 kg m/s²=> force = -7500 N negative sign denotes opposing force



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