Example 9.30In the equilibrium mixture, the concentration of hydrogene

1.	Example 9.30In the equilibrium mixture, the concentration of hydrogeneach while that of hydrogen iodidure, the concentration of hydrogen and iodine is 0.04 moles peror of hydrogen iodide is 0.08 moles per dm. Find K of the following reactionThH2(g) + 12 g2H1 (g)Given:[H2] = 0.04 mol/ dm3[2] = 0.04 mol/ dm3[HI] = 0.08 mol/dm3K = ?
Answer» ANSWER: Explanation: In the equilibrium mixture, the concentration of hydrogen each while that of hydrogen iodid ure, the concentration of hydrogen and iodine is 0.04 moles per or of hydrogen IODIDE is 0.08 moles per dm. Find K of the following reaction Th H2(g) + 12 g 2H1 (g) Given: [H2] = 0.04 MOL/ dm3 [2] = 0.04 mol/ dm3 [HI] = 0.08 mol/dm3 K = ?

Example 9.30In the equilibrium mixture, the concentration of hydrogeneach while that of hydrogen iodidure, the concentration of hydrogen and iodine is 0.04 moles peror of hydrogen iodide is 0.08 moles per dm. Find K of the following reactionThH2(g) + 12 g2H1 (g)Given:[H2] = 0.04 mol/ dm3[2] = 0.04 mol/ dm3[HI] = 0.08 mol/dm3K = ?

Answer»

Explanation:

In the equilibrium mixture, the concentration of hydrogen

each while that of hydrogen iodid

ure, the concentration of hydrogen and iodine is 0.04 moles per

or of hydrogen IODIDE is 0.08 moles per dm. Find K of the following reaction

H2(g) + 12 g

2H1 (g)

Given:

[H2] = 0.04 MOL/ dm3

[2] = 0.04 mol/ dm3

[HI] = 0.08 mol/dm3

K = ?