1.

Excess electrons are placed on a small lead sphere of mass `6.90 ` g so that its net charge is `-3.20 xx 10^(-9)C`. Find the number of excess electorns ( in terms of `xx 10^(10))` on the sphere.

Answer» `qq=n_(e)e` or `n_(e)=(-3.20xx10^(-9))/(-1.6xx10^(-9))=2.0xx10^(10)`


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